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Lead(II) nitrate solution reacts with potassium iodide solution to produce lead(II) iodide and potassium nitrate.

The answer in the book is:
Pb(NO3)2(aq) + 2 KI(aq) ---> 2KNO3(aq) + PbI2(s)

I understand how to write and balance the equation. However, I am confused about how to determine the states of matter. Why are some aqueous and one solid? Does it have something to do with the solubility rules? Thanks for your help.

  • Chemistry -

    PbI2 is not soluble in water; therefore, it is written as PbI2(s).
    KNO3 is soluble in water; therefore, in solution it is written as KNO3(aq).
    Pb(NO3)2(aq) means you have a solution of Pb(NO3)2 and not solid Pb(NO3)2.

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