A toy car coasts uphill at 2.34 m/s. It accelerates at -.34 m/s squared. How long will it take the car to stop.What equation would I use.
Vo = a * T
where a = 0.34 m/s^2 and Vo = 2.34 m/s
That is how long it takes to reach a velocity of zero.
(Ignore the minus sign on a)
Solve for T
t=(Vfinal - Vintial)/ acceleration
time= (0-2.34m/s)/ -.34m/s^2
time=6.88seconds
To find the time it takes for the toy car to stop, we can use one of the kinematic equations of motion. The equation that relates initial velocity (v₀), final velocity (v), acceleration (a), and time (t) is:
v = v₀ + at
In this case, the initial velocity (v₀) is 2.34 m/s, the acceleration (a) is -0.34 m/s² (negative value because it's decelerating), and the final velocity (v) will be 0 m/s since the car comes to a stop.
Plugging in the known values into the equation:
0 = 2.34 + (-0.34)t
Now, solve for time (t):
-0.34t = -2.34
Divide both sides by -0.34:
t = -2.34 / -0.34
t ≈ 6.882
Therefore, it will take the car approximately 6.882 seconds to come to a stop.