Algebra
posted by Esther .
Is there anybody out there that can give me the answer to this problem I have tried but I can't get it. I really need to turn in my work. Thank you (4,8); 2x+5y=4

You didn't state your problem.
Are you finding a new equation
parallel to the given line ?
perpendicular to the given line ?
?? 
2x + 5y = 4
Add 2x to both sides
5y = 2x + 4
divide both sides by 5
y = 2/5 y + 4/5
So, slope m = 2/5
Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = 2/5
m1 * m2 = 1
2/5 * m2 = 1
m2 = 1/(2/5)
m2 = 5/2
Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, 8)
8 = 5/2 (4) + b
8 = 20/2 + b
8 = 10 + b
18 = b
y = 5/2 x + b
y = 5/2 + 18
y = 5/2  18
Follow these exact steps.
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