algebra 2
posted by Jessica .
2X^49X^3+3X^2X5=0
Given that one root is 2+i, solve the equation.
So far I have it set up like this:
2X^49X^3+3X^2X5/X^24X+5
I don't know how to get the answer, I know that I have to use long division but when I started to try it I kept getting weird answers. Please Help

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