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Precalc

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Solve for x

log[1/3](x^(2) + x) - log[1/3] (x^(2) - x) = -1

Steps too please.

so far I tried this and I got 3 = (x+1) / (x-1)

  • Precalc -

    is that base 1/3? lets call that a.

    loga(x^2+x) - loga(x^2-x)=-1
    loga[(x^2+x)/(x^2-x)]=-1

    take the antilog of each side, base a
    (x+1)/(x-1)= a^-1

    looks like you are correct.

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