Precalc
posted by Amy .
Solve for x
log[1/3](x^(2) + x)  log[1/3] (x^(2)  x) = 1
Steps too please.
so far I tried this and I got 3 = (x+1) / (x1)

is that base 1/3? lets call that a.
loga(x^2+x)  loga(x^2x)=1
loga[(x^2+x)/(x^2x)]=1
take the antilog of each side, base a
(x+1)/(x1)= a^1
looks like you are correct.