A dartboard has the numbers 3, 6, 9, 12, 15, 19, 21, 25, 27, and 30 on it. What is the fewest number of darts that could be thrown if two darts tcannot land on the same number and if the sum of the scores must be 50?
No two numbers add to 50. Therefore we must use at least 3 numbers to get the sum.
25+19+6 = 50: a solution exists for 3 numbers.