Algebra 1
posted by Esther .
write an equation of the line containing the point and perpendicular to the given line (4,8); 2x+5y=4
I am having a very hard time, but I'm trying hard to study the steps for solving the problem.
Profoundly, thank you.

Did you see the answer to your post below?
Post your work so I can see where you are having trouble. 
Sorry, but, no, I didn't see the answer to my post. However,
(4,8); 2x+5y=4 is?
y=2x+4
y8=1/2
y8=1/2(x4)
Again, I don't really know what to do after this. I may not even be followin the steps right. However, I would really appreacite your help. Thank you a million. 
2x + 5y = 4
Add 2x to both sides
5y = 2x + 4
divide both sides by 5
y = 2/5 y + 4/5
So, slope m = 2/5
Perpendicular lines, the slopes are negative reciprocals of each other.
Slope = 2/5
m1 * m2 = 1
2/5 * m2 = 1
m2 = 1/(2/5)
m2 = 5/2
Now you have to find b, for the equation of the perpendicular line.
y = mx + b
m = 5/2
y = 5/2 x + b
P(4, 8)
8 = 5/2 (4) + b
8 = 20/2 + b
8 = 10 + b
18 = b
y = 5/2 x + b
y = 5/2 + 18
y = 5/2  18
Follow these exact steps.