Algebra 1

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write an equation of the line containing the point and perpendicular to the given line (4,-8); 2x+5y=4

I am having a very hard time, but I'm trying hard to study the steps for solving the problem.

Profoundly, thank you.

  • Algebra 1 -

    Did you see the answer to your post below?

    Post your work so I can see where you are having trouble.

  • Algebra 1 -

    Sorry, but, no, I didn't see the answer to my post. However,

    (4,-8); 2x+5y=4 is?

    y=-2x+4

    y-8=1/2

    y-8=1/2(x-4)

    Again, I don't really know what to do after this. I may not even be followin the steps right. However, I would really appreacite your help. Thank you a million.

  • Algebra 1 -

    2x + 5y = 4
    Add -2x to both sides
    5y = -2x + 4
    divide both sides by 5
    y = -2/5 y + 4/5
    So, slope m = -2/5

    Perpendicular lines, the slopes are negative reciprocals of each other.
    Slope = -2/5
    m1 * m2 = -1
    -2/5 * m2 = -1
    m2 = -1/(-2/5)
    m2 = 5/2

    Now you have to find b, for the equation of the perpendicular line.
    y = mx + b
    m = 5/2
    y = 5/2 x + b
    P(4, -8)
    -8 = 5/2 (4) + b
    -8 = 20/2 + b
    -8 = 10 + b
    -18 = b

    y = 5/2 x + b
    y = 5/2 + -18
    y = 5/2 - 18

    Follow these exact steps.

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