Math
posted by PLEASE HELP .
solve for h
A= 1/2(a +b)h
I've tired over and over but still can't find the answer

multiply both sides by 2
2A= (a+b)h
divide both sides by (a+b)
2A/(a+b) = h
all done.
Respond to this Question
Similar Questions

algebra 1 help
6(32)^2 over 3^22(3)(2)+2^2 6(32)^2 over 3^22(3)(2)+2^2 6(5)^2 over 9+12+4 6(5)^2 over 3+4 6(25)^2 over 7 6x150 over 7 900 over 7 am i correct with this can i go any further . 6(32)^2 over 3^22(3)(2)+2^2 6(32)^2 … 
Algebra 2
would some one please check these for me 1. divide x^236y^2 over 5x^2+30y divide (x^26xy) A: x+6y over (5x)(x^2+6y) 2. Add. Express your answer in simplest form. 2x 0ver x^2+15x+54 + 4over x+6 A: 6 over x+9 3. solve: (9 over x5) … 
checking answers 4 algerbra
1. simplify by removing the parenthses and collecting like terms. 83q  (39q38)=44q+38? 
Math Check
y^25y over y^27y+10 What did I do wrong.. for my answer i got (y+5) over (y2) and the correct answer is y over (y2)? 
math
Simplify 1 over 2 of 1 over 4 devide 1 over 3 all over 1 over 6 minus 3 over 4 plus 1 over 2 
Math
Use the compound interest formula A=P(1+r)^t and the given information to solve for r. A=9,000,000 P=80,000 t=40 I have done this problem over a over and still get the wrong answer. 
algebra
Use the compound interest formula A=P(1+r)^t and the given information to solve for r. A=9,000,000 P=80,000 t=40 I have done this problem over a over and still get the wrong answer. 
(Math)Simplifying using the laws of exponents
I need help with a few problems. 1.) (x^3/4 times y^1/3)^2/3 How is the answer x^1/2y^2/9 2.)(x^1/3 times y) (x^1/2 times y^4/3) How is the answer x^1/6 over y^1/3 3.)(4a^2b^7/2)^1/2 How is the answer 2a over b^3/4 4.) (x^2/3y^1/3 … 
alGEBRA 2 help please would appreciate
x over (x+3) x over(x3)=x^2+9 over X^29 solve for x and check answer 
Math Quiz
Math Quiz please help fast Write the following ratio in simplest form: 32 min:36 min (1 point) 8:9 8:36 32:9 128:144 2. Marie saved $51. On Wednesday, she spent $8 of her savings. What ratio represents the portion of her total savings …