I have the answer and would love confirmation. VERY APPRECIATED!
Find the LCM OF (1+2t), (1-4t^2), and (1-2t).
1-4t^2=(1+2t)(1-2t)
1+2t = 1+2t
1-4t^2= (1+2t)(1-2t)
1-2t = 1 - 2t.
The LCM for all numbers is
1-4t^2 = (1+2t)(1-2t)
Thank you
you are correct
thank u!
To find the LCM (Least Common Multiple) of the expressions (1+2t), (1-4t^2), and (1-2t), you need to factorize each expression and identify the common factors.
Starting with (1-4t^2), you correctly recognized that it is the difference of squares: (1-4t^2) = (1+2t)(1-2t).
Next, consider (1+2t) and (1-2t). These expressions are not factorizable further, so they are already in their prime factor form.
Now, you need to identify the common factors among the three expressions.
From the factorization of (1-4t^2) = (1+2t)(1-2t), you have (1+2t) and (1-2t) as common factors.
The LCM is obtained by multiplying all the factors together, but we only count common factors once. Therefore, the LCM of (1+2t), (1-4t^2), and (1-2t) is:
LCM = (1+2t) * (1-2t) = 1 - 4t^2
So, your answer is correct. The LCM is 1 - 4t^2.