Post a New Question

trigonometry. Math

posted by .

In a triangle PQR, angle Q=50 degrees,PR=5CM, QR=4CM. find angle P?

  • trigonometry. Math -

    Looks like the "ambiguous case" , or sometimes called the SSA setup, where A is NOT the contained angle

    sinP/4 = sin 50°/5
    sin P = 4sin50/5 = .61284
    angle P = 37.8° or 180-37.8 ° which is 142.2°

    but the second case would result in (angleR + 142.2+50) > 180, thus that case is not admissable.

    so angle P is 37.8°

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question