The electric potential energy stored in the capacitor of a defibrillator is 83 J, and the capacitance is 124 µF. What is the potential difference that exists across the capacitor plates?
_____________ V
W =0.5CV^2 = 83 Joules.
0.5 * 124*10^-6 * V^2 = 83,
62*10^-6 * V^2 = 83,
V^2 = 83 / 62*10^-6 = 1.3887*10^6,
V = sqrt(1.3887*10^6)
V = 1.1570*10^3 = 1157 Volts.
To find the potential difference (V) across the capacitor plates, we can use the formula:
V = √(2 * E / C)
Where:
V is the potential difference
E is the electric potential energy stored in the capacitor
C is the capacitance
In this case, the electric potential energy (E) is given as 83 J and the capacitance (C) is given as 124 µF, which is equivalent to 124 × 10^(-6) F.
Plugging these values into the formula, we have:
V = √(2 * 83 / (124 × 10^(-6)))
Simplifying the expression inside the square root:
V = √(166 × 10^(6) / 124 × 10^(-6))
V = √(1339.5)
Finally, calculating the square root:
V ≈ 36.59 V
Therefore, the potential difference that exists across the capacitor plates is approximately 36.59 V.