posted by Josie
Use a graph to estimate the limit:
lim θ->0 (sin(5θ)/θ)
Note: θ is measured in radians. All angles will be in radians in this class unless otherwise specified.
I tried graphing it on my calculator but the limit I got is incorrect.
Soon, if not already, you will come across this limit
limit sinx/x = 1, where x is in radians
your question "almost" looks like that, let's doctor it up so it does
lim sin(5Ø)/Ø as Ø ---> 0
= lim 5 sin(5Ø)/(5Ø) as Ø ---> 0
= lim 5 (1) = 5
When you tried it on your calculator, was it set to radians?
It worked on mine.