what is the molecular weight (G/mol) of a diprotic acid 0.43 sample that needed 35.46 ml of 0.100 M of NaOH solution to reach a phenolphthalein point?
moles of NaOH = .100 x 35.46 / 1000 = 0.003546
2NaOH + H2A = Na2A + 2H2O so moles of H2A = 0.001773
these are in .43 g so mass of 1 mole = .43 /0.001773
= 242.53 g / mole .. molar mass of the acid