Precalculus
posted by Amy .
1. Simplify the expression ((5x^2)/(4x^2))^2
2. (x)/(x^281)(9)/(81x^2) =
3. Let (3,3) and (6,_2) be points in the Cartesian plane. Find the distance between the points.

((5x^2)/(4x^2))^2
= (5x^2)(4x^2)^2
= (5x^2)(16x^4)
= 80x^2
2. Do you realize that 81  x^2 = (x^2  81)
so (x)/(x^281)(9)/(81x^2)
= x/(x^2  81) + 9/(x^2  81)
= (x9)/((x+9)(x9))
= 1/(x+9) , x ≠ 9 
for #3
you should have a formula for the distance between 2 points.
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