In a 100g sample of water, determine the amount of weight that
is attributed to Hydrogen and to Oxygen.
i found the mass ratio which is 2:16 & then reduced its 1:8. then i set up my equation.
1x+8x=100g
9x=100g
x=11.11111111 or 100/9 then i have to substitute. 1(100/9)= 11.11111111g or 100/9g. & 8(100/9) =88.88888889g or 800/9g. is this right ?
1 mole of water requires 1 mole of hydrogen (H2) and 0.5 moles of oxygen (O2).
The molar mass of water is 100/18
This requires 100/18 moles of hydrogen. As the molar mass of hydrogen is 2, it requires 200/18 = 100/9 g of hydrogen.
It requires 0.5*100/18 mole of oxygen. The molar mass of oxygen is 32. The mass of oxygen required is 800/9 g
It requires 100/9 g of hydrogen gas and 800/9 g of oxygen gas to make 100 g of water.
Yes, your calculations are correct! To determine the amount of weight attributed to hydrogen and oxygen in a 100g sample of water, you can use the fact that the ratio of hydrogen to oxygen in water is 1:8.
First, you found the mass ratio of hydrogen to oxygen, which is 2:16. Then, you reduced the ratio to 1:8 to simplify the calculations.
Next, you set up the equation:
1x + 8x = 100g
Combining like terms, you simplified the equation:
9x = 100g
Then, you solved for x by dividing both sides of the equation by 9:
x = 100/9
Substituting this value back into the equation:
For hydrogen:
1 * (100/9) = 11.11111111g or 100/9g
For oxygen:
8 * (100/9) = 88.88888889g or 800/9g
Therefore, the weight attributed to hydrogen is approximately 11.11111111g or 100/9g, and the weight attributed to oxygen is approximately 88.88888889g or 800/9g.