posted by .

log2(log4x)=1 and

solve for x and y:
(1/2)^x+y= 16 logx-y8=-3

## Similar Questions

2. ### Math

I am having trouble figuring out how to solve these logarithms. Could someone please help! log2(log4x)=1 and solve for x and y: (1/2)^x+y= 16 logx-y8=-3
3. ### Math

I am having trouble figuring out how to solve these logarithms. Could someone please help! log2(log4x)=1 and solve for x and y: (1/2)^x+y= 16 logx-y8=-3

I need help figuring this question out please :) log2=log(x+5)-1 I have been studying for my test and this is a question i got stuck on.
5. ### math

I tried everthing but,I couldn't solve it. Please help me.the answer at the back is 40960.13 question: solve for x and check your solution. logx/log2 + logx/log4 + logx/log8 + logx/log16 = 25 THANK YOU FOR YOUR KIND HELP!!!!
6. ### math

solve the equation. log2(x+4)-log4x=2 please show work
7. ### math

solve the equation log2(x+4)-log4x=2 the 2 and 4 are lower than the g This is what I got: log2(x+4)+log2(4^x)=2 log2((x+4)*4^x)=2 4^x(x+4)=4 x=0 is a solution?
8. ### advance functions gr 12

2 QUICK QUESTIONS PLEASE HELP ME I NEED THEM FOR THE MORNING! the ______________ (fill in blank) of logarithms state that log (xy)= logx + logy solve the equation 6^3x+1= 2^2x-3, Leave in extact form THANKS
9. ### Urgent math

i need help with these two homework problems Use the Laws of Logarithms to combine the expression into a single logarithm log2 5 − 5 log2 x + 1/2 log2(x + 1) Solve the logarithmic equation for x log2(x + 2) + log2(x − 1) …
10. ### logarithms maths

logx+logx+n-logx/n.plz solve with explanation thanks

More Similar Questions