# Math-Advanced Functions

posted by
**Chloe**
.

I am having trouble figuring out how to solve this logarithms. Could someone please help!

log2(log4x)=1 and

solve for x and y:

(1/2)^x+y= 16 logx-y8=-3

posted by
**Chloe**
.

I am having trouble figuring out how to solve this logarithms. Could someone please help!

log2(log4x)=1 and

solve for x and y:

(1/2)^x+y= 16 logx-y8=-3