after diving 93m below sea level, a diver rises at a rate of 6 meters per minute for 8 minutes. where is the diver in relation to the surface?
i can't figure this one out
6x8=72
72 + 93= 165
but this still doesn't look right at all!!!!!!!!
Nope, it isn't right.
To begin, 6 times 8 = 42
Visualize the diver going down 93 meters.
Then he comes back up 42 meters.
You can't add these together. What do you think you should do with these numbers?
Hi Ms.Sue,
I would subtract 93-42= 50
Oops -- neither one of us checked MY math. I had a typo in my multiplication.
6 * 8 = 48
93 - 48 = 45 meters below the surface
lol I came back just now to type about that.
also this problem has me lost
rewrite the division as a multiplication
-22/24= 22x?
and it states not to simplify write it as a fraction?
I have no clue but I tried this 1 1/22?
To determine the final position of the diver in relation to the surface, we need to consider both the initial depth below sea level and the rate at which the diver is rising.
Given that the initial depth below sea level is 93m, and the diver is rising at a rate of 6 meters per minute for a total of 8 minutes, we can calculate the total distance ascended as follows:
6m/minute * 8 minutes = 48m
Now, to find the final position in relation to the surface, we need to add the distance ascended to the initial depth below sea level:
93m + 48m = 141m
Therefore, the diver is located 141m below the surface after rising at a rate of 6 meters per minute for 8 minutes.