In a 100g sample of water, determine the amount of weight that

is attributed to Hydrogen and to Oxygen.

i found the mass ratio which is 2:16 & then reduced its 1:8. then i set up my equation.

1x+8x=100g
9x=100g
x=11.11111111 or 100/9 then i have to substitute. 1(100/9)= 11.11111111g or 100/9g. & 8(100/9) =88.88888889g or 800/9g. is this right ?

Your approach to solving the problem is correct, but there seems to be a small calculation error in your solution.

To determine the amount of weight attributed to hydrogen and oxygen in a 100g sample of water, you can use the fact that the atomic mass ratio of hydrogen to oxygen in water is 1:8.

Let's go through the steps again:

1. Start by setting up the equation using the ratio. Let x represent the weight attributed to hydrogen:

Hydrogen: 1x
Oxygen: 8x

1x + 8x = 100g

2. Combine like terms:

9x = 100g

3. Solve for x by dividing both sides of the equation by 9:

x = 100g / 9

After performing the division, you correctly calculated that x is approximately 11.11111111g or 100/9g.

4. Now, substitute this value of x back into the equation to find the weights attributed to hydrogen and oxygen:

Hydrogen: 1(100/9) = 100/9g or approximately 11.11111111g
Oxygen: 8(100/9) = 800/9g or approximately 88.88888889g

Therefore, the correct weights attributed to hydrogen and oxygen in the 100g sample of water are approximately 11.11111111g and 88.88888889g, respectively.