A Spring of force constant 300N/m is compressed such that its length shortens by 3cm. calculate the energy stored in the spring?. please Help
Energy=1/2 k .03^2, right?
To calculate the energy stored in a spring, you can use the formula:
Potential Energy (U) = (1/2) * k * x^2
Where:
U = Potential Energy stored in the spring
k = Force constant of the spring
x = Amount of compression or displacement from the equilibrium position
Given:
Force constant, k = 300 N/m
Shortening of length, x = 3 cm = 0.03 m
Substituting the given values into the formula:
U = (1/2) * 300 N/m * (0.03 m)^2
U = (1/2) * 300 N/m * (0.0009 m^2)
U = 0.135 Joules
Therefore, the energy stored in the spring is 0.135 Joules.
To calculate the energy stored in a spring, you can use the formula for the potential energy of a spring:
E = (1/2) * k * x^2
where:
E is the energy stored in the spring,
k is the force constant of the spring, and
x is the displacement or change in length of the spring.
In this case, the force constant (k) is given as 300 N/m, and the displacement (x) is given as 3 cm, which is equivalent to 0.03 m.
Now, substitute the known values into the formula:
E = (1/2) * 300 N/m * (0.03 m)^2
E = 0.45 J
Therefore, the energy stored in the spring is 0.45 Joules.