The Bob of a simple pendulm oscillates with an amplitude of 0.02m and a period of 0.5s, calculate the speed of the bob through the equilibrium position?. Please help
In simple harmonic motion such as this,
Maximum speed = w*A,
where w is the angular frequency and A is the amplitude.
The maximum speed is attained at the equilibrium position, and that is why we can use this formula.
In this case, w = 2 pi/0.5 = 4 pi
= 12.57 radians/s
maximum speed = w*A = 12.57*0.02 = 0.251 m/s