An aspirin tablet weighing 0.475 g has been analyzed and contains 68.2 % ASA (180.16 g/mol) by mass. A student dissolved
the tablet in hot NaOH and the cooled solution was diluted with DI water to the mark in a 250 mL volumetric flask. Exactly 3.00 mL
of the solution was pipetted into a 100 mL volumetric flask and diluted to the mark with FeCl3 solution.
The concentration of the diluted solution is
What kind of concn? M, m, %, g/mL, what? If M, then
g ASA in the tablet = 0.475 g x 0.682 = ??g ASA
??g/180.16 = xx moles ASA
M = xx moles/0.250L = yy M
Then yyM x (3/100) = zz M as the final answer.