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An aqueous antifreeze solution is 40.0% ethylene glycol (C2H6O2) by mass. The density of the solution is 1.05 g/cm3. Calculate the molality, molarity, and mole fraction of the ethylene glycol.

  • Chemistry -

    40% means 40 g ethylene glycol/100 g solution.
    40 g to moles = 40/molar mass.
    Use density to convert 100 g soln to volume, then M = moles/L.

    Convert % to m
    40g/100 g = 40g glycol/(40g glycol + 60 g water).
    Convert 40 g glycol to moles.
    Convert 60 g water to kg.
    m = moles/kg solvent.

    For mole fraction starting with 40% glycol.
    moles glycol = 40/molar mass
    moles solvent = 60 g/molar mass
    mole fraction glycol = moles glycol/total moles.

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