what is the volume of 250.0 grams of acetone whose density is 0.7899 g/cm
volume = mass/density
I assume that the units of the density of acetone are g cm^-3.
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To find the volume of a substance, you can use the formula:
Volume = Mass / Density
In this case, the mass of acetone is given as 250.0 grams, and the density of acetone is 0.7899 g/cm³.
To find the volume of acetone, you need to divide the given mass by the density:
Volume = 250.0 grams / 0.7899 g/cm³
First, we need to convert the density from grams per cubic centimeter (g/cm³) to grams per milliliter (g/mL) since the mass is given in grams.
To convert the density, you divide it by 1 cm³/1 mL:
0.7899 g/cm³ ÷ 1 cm³/1 mL = 0.7899 g/mL
Now that we have the density in grams per milliliter, we can calculate the volume:
Volume = 250.0 grams / 0.7899 g/mL
By dividing grams by grams per milliliter, the grams cancel out and we're left with milliliters (mL):
Volume = 316.5046 mL
Therefore, the volume of 250.0 grams of acetone with a density of 0.7899 g/cm³ is approximately 316.5046 mL.