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A box with a mass of 40.0 kg is pulled along a level floor at a constant speed by a rope that makes an angle of 20.0o with the floor as shown below. If the force on the rope is 200 N, then coefficient of sliding friction or ) between the box and the floor is:

a) 0.58
b) 0.48
c) 0.51
d) 0.30

  • physics -

    Fh = 200*cos20 = 187.9N.

    Fv = 40*9.8 + 200*sin20,
    Fv = 392 + 68.4 = 460.4N.

    Since the velocity is constant, the
    acceleration = 0:

    Fn = ma = 0, Fn = Net force,
    Fh - uFv = 0, uFv = force of friction.
    187.9 - 460.4u = 0,
    -460.4u = -187.9,
    u = -187.9 / -460.4 = 0.408.

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