how do you find the square root of 49x^5?
That would be 7*x^(5/2)
For a number, you would need to know the value of x.
x^(5/2) is the square root of x^5
where did you get the 2?
The square root of any number x can be written x^(1/2)
That way,
x^(1/2) * x^(1/2) = x^1 = x
To find the square root of 49x^5, we can break it down into its factors. The square root of a product is equal to the product of the square roots of its factors.
We can rewrite 49x^5 as (7^2) * x^2 * x^2 * x:
√(49x^5) = √(7^2 * x^2 * x^2 * x)
Taking the square root of each factor individually:
√(49) * √(x^2) * √(x^2) * √(x)
Simplifying:
7 * x * x * √x
The square root of 49 is 7, the square root of x^2 is x, and the square root of x is √x.
So, √(49x^5) simplifies to 7x^2√x.