A coach with a mass of 100 kg is placed on an adjustable ramp attached to a truck. As one end raises, the couch begins to move downward. If it sldes with an acceleration of .79 m/s^2 at 12 degrees, what is the coefficient of kinetic friction.

I think I found the normal force, but I don't think I found the correct force of friction. Any help would be nice. Thanks!

net force down the plane=mass*a

100g*sin12-mu*100g*cos12=mass*a
solve for mu. g = 9.8N/kg

I don't think I did it correctly. I got a very very small number.

To find the coefficient of kinetic friction in this scenario, you need to consider the forces acting on the coach.

First, let's find the normal force acting on the coach. The normal force (N) is the force exerted by a surface to support the weight of an object resting on it. In this case, the normal force is equal to the component of the gravitational force acting perpendicular to the ramp.

The formula for the normal force on an inclined plane is given by N = mg * cos(theta), where m is the mass of the coach and theta is the angle of inclination.

Given that the mass of the coach is 100 kg and the angle of inclination is 12 degrees, we can calculate the normal force:

N = 100 kg * 9.8 m/s^2 * cos(12 degrees)

Next, let's find the net force acting on the coach. The net force is equal to the mass of the coach multiplied by its acceleration (F_net = ma). In this case, the net force is the component parallel to the ramp, which causes the coach to accelerate.

Given that the acceleration of the coach is 0.79 m/s^2, we can calculate the net force:

F_net = 100 kg * 0.79 m/s^2

Now, let's calculate the force of friction acting on the coach. The force of friction (F_friction) can be found using the formula F_friction = coefficient of kinetic friction * N, where the coefficient of kinetic friction is what we need to find.

We can rearrange the equation to solve for the coefficient of kinetic friction:

coefficient of kinetic friction = F_friction / N

Substituting the values we have:

coefficient of kinetic friction = (100 kg * 0.79 m/s^2) / N

Finally, we substitute the value of N that we calculated earlier to find the coefficient of kinetic friction.