Write electron configurations for the following ions, and determine which have noble-gas configurations. (Type your answer using the format [Ar] 4s2 3d10 4p2 for [Ar]4s23d104p2.)

Ru2+

thanks

I,or someone will be happy to check your work.

If you don't know the electron configuration of Ru, check here. www.webelements.com

To determine the electron configuration of Ru2+, we first need to consider the electron configuration of the neutral atom, Ru. The atomic number for ruthenium (Ru) is 44.

The electron configuration of a neutral Ru atom is: 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d7

To form Ru2+, two electrons are removed from the outermost 5s orbital. So, the electron configuration of Ru2+ is: 1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p6 4d6

To determine if Ru2+ has a noble-gas configuration, we compare its electron configuration to the nearest noble gas element, which is argon (Ar).

The electron configuration of Ar is: 1s2 2s2 2p6 3s2 3p6.

Comparing the two configurations, we find that Ru2+ is [Kr] 4d6.

Therefore, Ru2+ does not have a noble-gas configuration.

To determine the electron configuration of an ion, we need to know the atomic number of the element. In this case, we are looking for the electron configuration of Ru2+ (Ruthenium).

The atomic number of Ruthenium (Ru) is 44.

First, let's write the electron configuration for Ru.

1. Write the electron configuration for the neutral atom:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s2 4d6

Next, we remove the appropriate number of electrons to form Ru2+, which means removing 2 electrons:

2. Remove 2 electrons from the highest energy level (remove them from 5s2):
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d6

Now, let's check if this electron configuration has a noble gas configuration. Noble gases have fully filled electron shells and are very stable. In this case, we can look for the nearest noble gas, which is Krypton (Kr).

The electron configuration of Kr is:
1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6

To compare this with the electron configuration of Ru2+, we can write both side by side:

Kr - [Kr] = 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6
Ru2+ - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 4d6

As we can see, the electron configuration for Ru2+ can be written as:
[Kr] 5s2 4d6

Since it starts with the noble gas configuration [Kr], the electron configuration for Ru2+ has a noble-gas configuration.