give the equation involved when 1 mole of ethane is completely burnt in air to get 2 moles of carbon dioxide and 3 moles of water
C2H6 + (7/2)O2 ==> 2CO2 + 3H2O
To determine the equation for the complete combustion of 1 mole of ethane (C2H6) in air to produce 2 moles of carbon dioxide (CO2) and 3 moles of water (H2O), we need to balance the equation by following these steps:
Step 1: Write the unbalanced equation.
C2H6 + O2 → CO2 + H2O
Step 2: Balance the carbon atoms.
The unbalanced equation has 2 carbon atoms on the left and 1 carbon atom on the right. To balance this, multiply CO2 by 2 on the right side.
C2H6 + O2 → 2CO2 + H2O
Step 3: Balance the hydrogen atoms.
The unbalanced equation has 6 hydrogen atoms on the left and 2 on the right. To balance this, multiply H2O by 3 on the right side.
C2H6 + O2 → 2CO2 + 3H2O
Step 4: Balance the oxygen atoms.
The unbalanced equation has 2 oxygen atoms in ethane and 2 oxygen atoms in carbon dioxide on the left, but only 3 oxygen atoms in water on the right. Since there are 3 oxygen atoms in air, we need to balance it. To do this, we multiply O2 by 3 on the left.
C2H6 + 3O2 → 2CO2 + 3H2O
Now, we have the balanced equation:
C2H6 + 3O2 → 2CO2 + 3H2O
This equation represents the complete combustion of 1 mole of ethane in air to produce 2 moles of carbon dioxide and 3 moles of water.