What is gravitational force of a 65kg person that is on the surface of the moon has a mass of 7.348 x 10^22kg and radius of 1731km?

To calculate the gravitational force experienced by a person on the surface of the moon, we can use the formula for gravitational force:

F = (G * m1 * m2) / r^2

where F is the gravitational force, G is the gravitational constant (approximately 6.67430 x 10^-11 Nm^2/kg^2), m1 and m2 are the masses of the two objects, and r is the distance between their centers.

In this case, the mass of the person (m1) is 65 kg, the mass of the moon (m2) is 7.348 x 10^22 kg, and the radius of the moon (r) is 1731 km (which we'll need to convert to meters).

Let's now calculate the gravitational force:

Step 1: Convert the radius of the moon from kilometers to meters:
r = 1731 km * 1000 = 1,731,000 meters

Step 2: Substitute the known values into the formula to calculate the gravitational force:
F = (6.67430 x 10^-11 Nm^2/kg^2) * (65 kg) * (7.348 x 10^22 kg) / (1,731,000 meters)^2

Step 3: Simplify and solve the equation:
F = (6.67430 x 10^-11 Nm^2/kg^2) * (65 kg) * (7.348 x 10^22 kg) / (2.995361 x 10^12 meters^2)
F ≈ 1.625716 x 10^3 N

Therefore, the gravitational force experienced by a 65 kg person on the surface of the moon is approximately 1.625716 x 10^3 Newtons.