What is the surface area of a right circular cylinder with base circle of radius of 5m and height of the cylinder 10m?
SA = 2 pi r^2 + 2 pi r h
r = 5, h = 10
SA = 2(3.14)(5^2) + 2(3.14)(5)(10)
I'll leave the math to you.
express answer in sq m
Acylandar has a radius of 8 cm and a height of ro cm. Explain wheather tripiling the height will tripple the volume of the cylindar.
To find the surface area of a right circular cylinder, we can break it down into two parts: the area of the two circular bases and the area of the curved surface.
The formula for the surface area of a right circular cylinder is:
Surface Area = 2πr² + 2πrh
where:
- r is the radius of the base circle
- h is the height of the cylinder
In this case, the radius of the base circle is given as 5m, and the height of the cylinder is given as 10m.
To find the area of the circular bases, we use the formula for the area of a circle:
Area of a circle = πr²
Therefore, the area of each circular base is:
Area of the base = π(5)² = π(25) = 25π square meters
Next, we calculate the area of the curved surface:
Curved Surface Area = 2πrh
Substituting the values, we get:
Curved Surface Area = 2π(5)(10) = 100π square meters
Finally, we can calculate the surface area by adding the area of the two circular bases and the area of the curved surface:
Surface Area = 2(25π) + 100π
Surface Area = 50π + 100π
Surface Area = 150π
The surface area of the right circular cylinder with a base circle radius of 5m and a height of 10m is 150π square meters.