Farhan is in a hurry to tidy up. without looking at the cases of 3 cds, farhan just puts the cds into the cases. how many different ways can the 3 cds be put into the cases?
please show me what work you use to do this? im super confused. thx
6 Different Ways:
1, 2, 3.
2, 3, 1.
3, 1, 2.
3, 2, 1.
2, 1, 3.
1, 3, 2.
3!
3*2*1=6
To determine the number of different ways the 3 CDs can be put into the cases, we can use the concept of permutations.
Let's break the problem down step by step:
Step 1: Consider the first CD. It can be placed in any of the three cases (since there are three cases available).
Step 2: Now, consider the second CD. It can also be placed in any of the three remaining cases. So, for each of the three possibilities in Step 1, we have three possibilities in Step 2, giving us a total of 3 * 3 = 9 possibilities.
Step 3: Finally, consider the third CD. Like before, it can be placed in any of the remaining two cases. So, for each of the nine possibilities from Step 2, we have two possibilities in Step 3, resulting in a total of 9 * 2 = 18 possibilities.
Therefore, there are 18 different ways the 3 CDs can be put into the cases without looking.
To summarize:
1st CD: 3 possibilities
2nd CD: 3 possibilities for each of the 3 possibilities in Step 1, totaling 9 possibilities
3rd CD: 2 possibilities for each of the 9 possibilities in Step 2, totaling 18 possibilities
Hence, there are 18 different ways to put the 3 CDs into the cases.