Whenever you use a inclined plane a. deis ezual to dr b. dris zero, c. deis less than dr, d. de is greater than dr
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And you probably will need to proofread and clarify what you posted. It doesn't make a whole lot of sense.
When using an inclined plane, the force required to move an object up or down this slope depends on the angle of inclination. In order to determine the relationship between the effort force, or force applied by pushing or pulling the object, and the resistance force, or the weight of the object being moved, we can use trigonometry.
Let's consider the situation where an object is being moved up an inclined plane. The force of gravity acting on the object, which is the resistance force, can be broken down into two components: one acting parallel to the inclined plane (called the "weight component along the plane") and the other perpendicular to the plane (called the "weight component perpendicular to the plane").
The weight component that acts parallel to the plane (or the resistance force) can be determined by multiplying the weight of the object by the sine of the angle of inclination (θ). This is expressed as Wsinθ, where W represents the weight. This force is directed downward, opposing the upward motion.
On the other hand, the force required to move the object up the inclined plane is known as the effort force, or force exerted. This force acts parallel to the inclined plane and is directed upward.
Now, let's answer your question based on this information:
a. Is de equal to dr?
The effort force (de) is equal to the weight component along the plane (dr) only when there is no friction present on the inclined plane. This means that the object slides up the slope without any resistance due to friction.
b. Is dr equal to zero?
The weight component along the plane (dr) is not zero, except in the absence of any gravitational force acting upon the object or in a situation where the inclined plane is completely vertical (θ = 90°). In most cases, there will be a nonzero resistance force acting along the plane.
c. Is de less than dr?
The effort force (de) is generally less than the resistance force (dr) when moving an object up an inclined plane. This is because the resistance force depends on the weight of the object, whereas the effort force is the force applied by pushing or pulling. Due to the inclined plane, the effort force required is reduced compared to lifting the object straight up.
d. Is de greater than dr?
In most cases, the effort force (de) is greater than the resistance force (dr) when moving an object up an inclined plane. This is particularly true if the angle of inclination is steep. In such cases, more effort force is necessary to overcome the resistance caused by the weight component along the plane.
To summarize, the correct answer to your question is generally:
c. de is less than dr