algebra

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Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 19 less than three times the number of pennies. How many coins of each kind does she have?

  • algebra -

    p = pennies
    2p - 9 = nickles
    3p - 19 = dimes

    p + 2p - 9 + 3p - 19 = 140
    6p - 28 = 140
    6p = 168
    p = 28

    p = pennies = 28
    2p - 9 = nickles = 47
    3p - 19 = 65

  • algebra -

    there are 100 coins. ten are dimes. the rest are pennies and nickles. there are twice as many pennies as nickles. how many pennies and nickles are in the jar?

  • algebra -

    Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

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