algebra
posted by Brittney .
Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 9 less than twice the number of pennies; the number of dimes she has is 19 less than three times the number of pennies. How many coins of each kind does she have?

p = pennies
2p  9 = nickles
3p  19 = dimes
p + 2p  9 + 3p  19 = 140
6p  28 = 140
6p = 168
p = 28
p = pennies = 28
2p  9 = nickles = 47
3p  19 = 65 
there are 100 coins. ten are dimes. the rest are pennies and nickles. there are twice as many pennies as nickles. how many pennies and nickles are in the jar?

Suppose that Maria has 140 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 12 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?
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