MathAlgebra
posted by Darryl .
Solve: 3x2y=10 2x+3y=2
Graph:
Substitution:
Elimination:
Show Your work!
(I can'tfigure out how to graph it and when i used substitution and elimination it came out with two different anwsers. I need help! and i need to be able to show my work!)

Eq1: 3X  2Y = 10.
Eq2: 2X + 3Y = 2.
Substitution Method:
In Eq2, solve for X:
Eq2: 2X + 3Y = 2,
2X = 3Y  2,
X = 3Y/2  1,
In Eq1, substitute 3Y/2  1 for X:
3(3X/2  1)  2Y = 10,
9X/2  3  2Y = 10,
Multiply both sides by 2 and get:
9X  6 4Y = 20,
13Y = 20 + 6,
13Y = 26,
Y = 26 / 13 =  2.
In Eq2, substitute 2 for Y:
2X + 3*2 = 2,
2X  6 =  2,
2X = 2 + 6,
2X = 4,
X = 4 / 2 = 2.
Solution Set = (2, 2).
Elimination Method:
Multiply Eq1 by 2 and Eq2 by 3 and get:
6X + 4Y = 20,
+6X + 9Y = 6
Add the 2 Eqs and get:
13Y = 26,
Y = 26 / 13 = 2.
Substitute 2 for Y in Eq1:
3X  2*2 = 10,
3X + 4 = 10,
3X = 10  4,
3X = 6,
X = 6 / 3 = 2.
Solution Set = (2, 2).
GRAPH: Use the following points.
Eq1:(2, 8) (0, 5), (2, 2).
Eq2: (2.5, 1),(4, 2) (2, 2).
The point where the lines intersect is the solution.
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