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Algebra II

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The base of a triangle is 8 cm greater than the height. The area is 24cm^2. What is the base and height?

  • Algebra II -

    Let height is x.
    So base=x+8
    area of triangle=1/2*b*h
    given area=24
    so 24=1/2*b*h
    2*24=(x+8)*x
    48=(x^2+8x)
    x^2+8x-48=0
    x^2+(12x-4x)-48=0
    x^2+12x-4x-48=0
    x(x+12)-4(x+12)=0
    (x+12)(x-4)=0
    x=4,-12
    so taking x=4
    height=4cm
    base=x+8=4+8=12cm

  • Algebra II -

    jjik

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