what masses of Mg and O2 must be contained to make exactly 2000g of Mgo

Figure the percentage composition of MgO

percent Mg: atomicmassMg/(atomicmassMg+atomicmassO)

massMg required= percentMg*2000
massO required=2000-massMg

To determine the masses of Mg and O2 required to produce 2000g of MgO (magnesium oxide), we need to first understand the chemical equation representing the reaction between Mg and O2. The balanced equation is:

2Mg + O2 -> 2MgO

From the equation, we can see that it takes 2 moles of Mg to react with 1 mole of O2 to form 2 moles of MgO. Now we can calculate the masses.

Step 1: Calculate the molar mass of MgO:
- Molar mass of Mg = 24.31 g/mol
- Molar mass of O = 16.00 g/mol
- Molar mass of MgO = (24.31 g/mol) + (16.00 g/mol) = 40.31 g/mol

Step 2: Determine the number of moles of MgO:
- Moles of MgO = mass of MgO / molar mass of MgO
- Moles of MgO = 2000 g / 40.31 g/mol = 49.58 mol (rounded to two decimal places)

Step 3: Calculate the moles of Mg:
- Since the ratio of MgO to Mg is 2:2, we know the moles of Mg will also be 49.58 mol.

Step 4: Convert the moles of Mg to mass:
- Mass of Mg = moles of Mg * molar mass of Mg
- Mass of Mg = 49.58 mol * 24.31 g/mol = 1204.42 g (rounded to two decimal places)

Step 5: Determine the mass of O2:
- From the balanced equation, we know that 1 mole of O2 reacts with 2 moles of Mg.
- So, the ratio of O2 to Mg is 1:2.

- Moles of O2 = (moles of Mg) / 2
- Moles of O2 = 49.58 mol / 2 = 24.79 mol (rounded to two decimal places)

Step 6: Convert the moles of O2 to mass:
- Mass of O2 = moles of O2 * molar mass of O2
- Mass of O2 = 24.79 mol * 32.00 g/mol = 792.71 g (rounded to two decimal places)

Therefore, to obtain exactly 2000g of MgO, you would need approximately 1204.42g of Mg and 792.71g of O2.