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If the voltage between the two plates of an electric air cleaner is 500 V, how fast would a 10-12 kg soot particle with -1 x 10-11 C of charge on it be moving if it went from the negative plate to the positive?

  • please -

    The electrical potential energy loss,
    q*V = 5*10^-9 J ,
    would equal the kinetic energy gain when it hits the opposite plate,
    (1/2) M V^2

    V = sqrt(2 q V/M) = 100 m/s

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