polynomial
with h+vt-4.9^2
50 meters high
30 meters per sec.
what is height after 2 sec.
Plug the values in.
h = 50m
t = 2s
v = 30m/s
h+vt+4.9*t^2=?
h+vt-4.9 t^2 (typo)
from
h = Ho + Vo t + (1/2) a t^2
where a = gravity = 9.8 m/s^2
Ho, initial height = 50m
Vo = initial velocity up = 30
so
50 + 30 (2) - 4.9 (4)
= 110 - about 20 = about 90
you use your calculator
typo a = -9.8m/s^2
(down)
To find the height after 2 seconds using the given polynomial equation, you need to substitute the values of h, v, and t into the equation and solve for the height.
The given polynomial equation is: h + vt - 4.9t^2
Let's substitute the given values into the equation:
h = 50 meters (initial height)
v = 30 meters per second (initial velocity)
t = 2 seconds (time)
Now plug in these values:
h + vt - 4.9t^2 = 50 + 30(2) - 4.9(2)^2
Next, simplify the equation:
h + vt - 4.9t^2 = 50 + 60 - 4.9(4)
h + vt - 4.9t^2 = 50 + 60 - 19.6
h + vt - 4.9t^2 = 110 - 19.6
h + vt - 4.9t^2 ≈ 90.4
Therefore, the height after 2 seconds is approximately 90.4 meters.