if 200mg of HCl is added to water to achieve a final volume of 1.00 L, what is the final pH?
To determine the final pH of the solution after adding 200mg of HCl to water, we need to consider the dissociation of HCl in water.
Step 1: Convert the mass of HCl to moles.
Given that the molar mass of HCl is 36.46 g/mol:
200 mg HCl = 0.2 g HCl
0.2 g HCl / (36.46 g/mol) = 0.00548 mol HCl
Step 2: Calculate the concentration of HCl.
Since the final volume is 1.00 L:
Concentration of HCl = 0.00548 mol HCl / 1.00 L = 0.00548 M
Step 3: Determine the pH of the solution.
HCl is a strong acid, which fully dissociates in water, releasing one H+ ion for every HCl molecule. Therefore, the concentration of H+ ions is equal to the concentration of HCl.
pH = -log[H+]
pH = -log(0.00548)
pH ≈ 2.26
Therefore, the final pH of the solution after adding 200mg of HCl to water and achieving a final volume of 1.00 L is approximately 2.26.
To determine the final pH of a solution, you need to know the concentration of hydrogen ions (H+) in the solution. In this case, 200 mg of HCl is added to water with a final volume of 1.00 L. However, the concentration of HCl is not provided, so let's calculate it.
First, convert the mass of HCl to moles. The molar mass of HCl is 36.46 g/mol. Therefore, 200 mg is equal to 0.2 g.
Next, convert grams of HCl to moles:
moles = mass / molar mass
moles = 0.2 g / 36.46 g/mol ≈ 0.0055 mol
Since the final volume is 1.00 L, the concentration of HCl can be calculated as follows:
concentration (C) = moles / volume
C = 0.0055 mol / 1.00 L
C = 0.0055 M
Now, since HCl is a strong acid, it fully ionizes in water, releasing H+ ions. Therefore, the concentration of H+ ions is equal to the concentration of HCl.
Therefore, the concentration of H+ ions is 0.0055 M.
To find the pH, we need to convert the concentration of H+ ions to a logarithmic scale:
pH = -log[H+]
Substituting the given value:
pH = -log(0.0055)
pH ≈ 2.259
Therefore, the final pH of the solution is approximately 2.259.
200 mg HCl = ?? moles.
0.200 g/molar mass HCl = moles.
Since HCl is a strong acid (it ionizes 100%), that will be the (H3O^+) in 1.00 L, therefore, M is that amount.
Then pH = -log(H3O^+).