roll 2 standard dice and add the numbers. what is the probability of getting a number larger than 9 for the first time on the third roll?
If you make a table for all the combinations of rolling dice you will notice that there are 6/36 possible ways to roll a sum greater than a nine. You are going to roll the dice 3 times and you do not want the sum of greater than 9 on the first 2 rolls but you do want a sum great than 9 on the 3rd roll. Look at the favorable probability for each one and then multiply them together. So 1st roll probability not greater than 9 30/36. 2nd roll probability not greater than 9 30/36. 3rd roll probability greater than 9 6/36. Multiply 30/36 * 30/36 * 6/36.
A die is rolled once. The probability of obtaining an odd number is
11.5%
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When a dice is rolled what is probability that it lands on An odd number
To find the probability of getting a number larger than 9 for the first time on the third roll when rolling two standard dice, we need to first list all the possible outcomes for rolling two dice.
When rolling two standard dice, there are 6 possible outcomes for each dice, resulting in a total of 6 * 6 = 36 possible outcomes when rolling both dice.
Next, we need to determine the number of favorable outcomes, which in this case are the outcomes where the sum of the numbers rolled is larger than 9 for the first time on the third roll.
To do this, let's list all the favorable outcomes:
Third roll: (4, 6), (5, 6), (6, 4), (6, 5), (6, 6)
Therefore, there are 5 favorable outcomes out of 36 possible outcomes.
To calculate the probability, divide the number of favorable outcomes by the number of possible outcomes:
Probability = Number of Favorable Outcomes / Number of Possible Outcomes
Probability = 5 / 36
The probability of getting a number larger than 9 for the first time on the third roll when rolling two standard dice is 5/36.