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the perimeter of isosceles triangle is 70 d. of the length of a leg of the triangle is 5 dm less than twice the lenth of the base, find the lengths of the sides of the triangle.

  • math -

    Let x = length of base, then 2x-5 = length of legs (sides).

    2(2x-5) + x = 70

    Solve for x.

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