If faucet is dripping at a rate of one drop per second and each drop contains 0.150 milliliters. Calculate how much water will be lost in 1 year.

1. If a faucet is dripping at a rate of one drop per second, and each drop contains 0.05 ml (milliliters), calculate how much water (in liters) will be lost in one year. (write your calculation out, a single number answer is not acceptable)

Number of seconds in a year, N

= 365*24*60*60 seconds/year

Volume of one drop, v
= 0.15 ml/second

Water lost in a year
= N * v ml/year

To calculate the amount of water lost in 1 year, we need to calculate the number of drops in one year and then convert it to the volume of water lost.

Step 1: Calculate the number of drops in one year
There are 60 seconds in a minute, 60 minutes in an hour, and 24 hours in a day. So, there are 60 x 60 x 24 = 86,400 seconds in a day.
There are 365 days in a year. Therefore, in one year, there are 86,400 x 365 = 31,536,000 seconds.

Since the faucet is dripping at a rate of one drop per second, the number of drops in one year is 31,536,000 drops.

Step 2: Calculate the volume of water lost in one year
Each drop contains 0.150 milliliters of water. So, the volume of water lost in one year is 31,536,000 x 0.150 = 4,730,400 milliliters.

Therefore, the faucet will lose 4,730,400 milliliters (or approximately 4,730.4 liters) of water in one year.

473000 litres