Cher has forgotten the combination to her locker. She knows it consists of four numbers -- 3, 5, 7, and 9 -- but she can't recall the order. She decides to try every possible order until she gets the right one.

How many possible orders are there?

The Correct Answer is: 24 orders

Four possibilities for the first number.

Four possibilities for the second number

Therefore, 4x4 = 16 possibilities for the first two numbers.

Four possibilities for the third number

Therefore, 16x4 = 64 possibilitites for the first three numbers.

I think you can now see what the total number of arrangements of all four numbers will be.

6 orders

To determine the number of possible orders, we need to calculate the number of permutations of the four numbers -- 3, 5, 7, and 9.

We can use the formula for permutations, which is given by n! / (n - r)!, where n is the total number of items and r is the number of items taken at a time.

In this case, we have four numbers and we want to arrange all four of them, so n = 4 and r = 4. Plugging these values into the formula:

4! / (4 - 4)! = 4! / 0! = 4 x 3 x 2 x 1 / 1 = 24.

Therefore, there are 24 possible orders for Cher's locker combination.

im pretty sure its 256. These r permutations right

Cher has forgotten the combination to her locker. She knows it consists of four numbers - 3, 5, 7, and 9 - but she can’t recall the order. She decides to try every possible order until she gets the right one. How many possible orders are there?