Math
posted by Emily .
if log(x+1) 27=3 find the value of x
*(x+1) is the base
i know that the answer is 2 but i have no clue how to get that

log(x+1) 27=3
since,
logb N = x
b^x = N
this can be written as
(x + 1)^3 = 27
take cube root of each side
x + 1 = 3
x = 2