math/trig
posted by Michael .
I have two questions as I review for a test tommorow, any help is much appreciated!!
Solve:
1) 4sin^2x=2cosx+1
2) cscx+cotx=1
Respond to this Question
Similar Questions

calculus
express in sinx 1 1  +  cscx + cotx cscx  cotx and express in cosx 1 + cot x   sin^2x cscx = 1/sinx so what do i do w. that extra one on the top!? 
trig
express this in sinx (1/ cscx + cotx )+ (1/cscx cotx) i got 2sinx is that right? 
Trig
Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (x=theta BTW) 
drwls
My previous question: Verify that (secx/sinx)*(cotx/cscx)=cscx is an identity. (secx/sinx)*(cotx/cscx) = (secx/cscx)(cotx/sinx) = (sinx/cosx)*cotx*(1/sinx) "The last steps should be obvious" Not to me. I can convert (sinx/cosx) to … 
trig
cosxcscx2cosx=cscx2 
AP calculus BC
hello i know that deriv(cscx) = cscxcotx and that deriv(cos) = sinx deriv(cotx) = ((cscx)^2) my question is: is this (statements below) correct? 
math/trig
I have two questions as I review for a test tommorow, any help is much appreciated!! Solve: 1) 4sin^2x=2cosx+1 2) cscx+cotx=1 
Trig
prove (cscxsecx/cscx+secx)=(cotx1/cotx+1) 
trig
Prove (cscx+cotx)(cscxcotx)=1 
Precalculus/Trig
I can't seem to prove these trig identities and would really appreciate help: 1. cosx + 1/sin^3x = cscx/1  cosx I changed the 1: cosx/sin^3x + sin^3x/sin^3x = cscx/1cosx Simplified: cosx + sin^3x/sin^3x = cscx/1cosx I don't know …