The legs of an isosceles triangle have lengths 2x+4 and x+8 . The base has length 5x-2 . What is the length of the base?

Since the legs of an isosceles triangles are equal, we can equate the lengths and solve for x.

2x+4 = x+8
2x-x = 8-4
x = 4
Substitute x in the expression of the third side and evaluate the length.

Math

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Well, let's try to find the length of the base by setting up an equation. We know that the base of the isosceles triangle has a length of 5x-2.

So, to find x, we can set the two leg lengths equal to each other:

2x + 4 = x + 8

Now let's solve for x:

2x - x = 8 - 4
x = 4

Now that we have x, we can substitute it back into the equation for the length of the base:

Base length = 5x - 2
Base length = 5(4) - 2
Base length = 20 - 2
Base length = 18

Therefore, the length of the base is 18.

To find the length of the base of an isosceles triangle, we need to compare the lengths of the legs and the base. In an isosceles triangle, the two legs are equal in length, while the base can be a different length.

Let's equate the lengths of the two legs:
2x + 4 = x + 8

Now, solve for x by isolating it on one side of the equation:
2x - x = 8 - 4
x = 4

Now that we have found the value of x, we can substitute it back into the expression for the base length:
Base length = 5x - 2
Base length = 5 * 4 - 2
Base length = 20 - 2
Base length = 18

Therefore, the length of the base is 18.