Physics
posted by Tara .
Original Question:
A block hangs in equilibrium from a vertical spring. When a second identical block is added, the original block sags by 5.00 cm. What is the oscillation frequency of the two block system?
bobpursley s'ltn:
F=kx = mg
x=mg/k
but for the second block we have
x+.05=2mg/k
setting the x equal..
mg/k2mg/k=.05
mg/k=.05
k= mg/.05
now frequency:
f= 1/2pi sqrt (k/m)
put that k int the expression, and you have the answer
Okay bob, I did that and got 0.112 when my calculator was in degrees, but I know it needs to be in radians. So I got 21.99 when my calculator was in radians. I think I may just be entering it into my calculator incorrectly.

When I initially did it I got 2.23Hz.. which was also incorrect.
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