math
posted by Alex .
Three brothers divide 17 candy bars. The oldest child gets 1/2, the middle child 1/3, and the youngest child 1/9. So that they do not have to cut any bars, Mom provides an extra one. The oldest chidl then takes 9 candy bars, the middle child 6, and the youngest 2, and they return the extra one. Which child received more than his fair share?

The oldest brother gets half a candy bar extra.

can someone explain that??? because if you do 1/2 of 17, 1/3 of 17, and 1/9 of 17 than compare it to what they actually got...they ALL got more than their fair share... is that the answer than? how is it just the oldest???

Well it means which got the most extra so ya it would be the oldest.

so what is the answeR?
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