The grams of oxygen that would produce 13.4 g Cl^2O^7 molecules.
The fraction of a Cl2O7 molecule's mass that is oxygen is
(16*7)/[16*7 + 2*35.5)
= 112/183 = 0.612
Multiply that by 13.4 g for the answer.
Thank you.
To determine the grams of oxygen required to produce a given number of molecules of Cl2O7, we need to use the molar ratio between Cl2O7 and oxygen atoms.
First, we need to find the molar mass of Cl2O7. This can be calculated by adding up the atomic masses of its constituent elements:
Molar mass of Cl2O7 = (molar mass of Cl * 2) + (molar mass of O * 7)
Next, use Avogadro's number to convert the number of molecules into moles:
Moles of Cl2O7 = Number of molecules / Avogadro's number
Now, we can determine the amount of oxygen in moles using the balanced chemical equation. From the equation, we know that 1 mole of Cl2O7 contains 7 moles of oxygen atoms. Therefore:
Moles of oxygen = Moles of Cl2O7 * 7
Finally, we can calculate the mass of oxygen in grams using the molar mass of oxygen:
Mass of oxygen = Moles of oxygen * molar mass of O
Now, let's calculate the grams of oxygen required to produce 13.4 g of Cl2O7 molecules:
1. Calculate the molar mass of Cl2O7:
Molar mass of Cl = 35.45 g/mol
Molar mass of O = 16.00 g/mol
Molar mass of Cl2O7 = (35.45 * 2) + (16.00 * 7) = 301.27 g/mol
2. Convert the number of molecules to moles:
Moles of Cl2O7 = 13.4 g / 301.27 g/mol
3. Calculate the moles of oxygen:
Moles of oxygen = Moles of Cl2O7 * 7
4. Calculate the mass of oxygen in grams:
Mass of oxygen = Moles of oxygen * molar mass of O
By following these steps, you should be able to find the grams of oxygen required to produce 13.4 g of Cl2O7 molecules.