baseball thrown horizontally takes 1.1 seconds to reach the ground. What is the height at which the ball was thrown?
H = (g/2) t^2
To find the height at which the baseball was thrown, we can use the kinematic equation for vertical motion. The equation is:
h = (1/2) * g * t^2
where:
h is the height
g is the acceleration due to gravity (approximately 9.8 m/s^2)
t is the time of flight (1.1 seconds in this case)
Now, substitute the values into the equation:
h = (1/2) * 9.8 * (1.1)^2
= (1/2) * 9.8 * 1.21
= 5.5 * 1.21
= 6.655 meters
Therefore, the height at which the baseball was thrown is approximately 6.655 meters.